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Видео ютуба по тегу Evaluate: Lim (X→0) ((Ex – 1 – X)
Evaluate limit x tend to infinity (a^(1/x)-b^(1/x))/log(x/(x-1)) indeterminate form l hospital rule
Evaluate lim(x→1) x/(x-1)-(1/logx) || limit x tend to 1 x/(x-1)-1/logx | ∞-∞ form indeterminate form
example 9 show that limit x tend to 0 (e^x+log(1-x/e))/(tanx-x) = -1/2 use l hospital rule
Evaluate: lim(x→0) (1/(e^x-1)-1/x) | limit x tend to 0 1/(e^x-1)-1/x ( ∞-∞ form ) indeterminate form
Evaluate lim(x→0) (e^xsinx-x-x^2)/(x^2+xlog(1-x)) using l hospital rule | indeterminate form
Evaluate: lim(x→0) (e^x -e^-x -2log(1+x))/xsinx
Evaluate: lim(x→0) (xe^x –log(1-x))/x^2 using l hospital rule
Show that lim(x→0) ((1+x)^1/x -e+ex/2)/x^2 =11e/24 || limit x tend to 0 ((1+x)^(1/x)-e+ex/2)/x^2
Show that lim(x→0) ((1+x)^1/x -e)/x =-e/2 || limit x tend to 0 ((1+x)^1/x-e)/x indeterminate form
Evaluate: lim (x→0) (e^x -e^sinx)/(x - sinx)
Evaluate lim (x→0) (e^x + e^-x - 2) / x²
Limit of sin(1/x) as x approaches 0 Does Not Exist | Calculus 1 Exercises
Evaluate limit x tends to infinity (1+1/x)^x
Evaluate : lim (x→0) (eˣ – 1 – x)/x²
Evaluate lim (x → 0) (e^ax - e^bx) / x
Evaluate : lim (x → 0) (e^x - e^-x) / x
Limit of e^x-1/x as x approaches 0
lim x → 0 (e^x-1)/x = 1 || lim x tends to zero e^x-1/x
Using L hospital rule lim x tends to zero x.e^x-log(1+x)/x^2
lim x~0 {(e^x – 1) tanx}/(x²) ✅ Evaluate using L-Hospital's rule. Class-12 Maths. Sukunda.
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